Find two consecutive even integers such that four times the first plus three times the second is 20

2 consecutive even integers : x and x + 2

4 (x) + 3 (x + 2) = 20

4x + 3x + 6 = 20

7x + 6 = 20

7x = 20 - 6

7x = 14

x = 14/7

x = 2

x + 2 = 2 + 2 = 4

so ur first number (x) = 2 and ur second number (x + 2) = 4