Write the quadratic equation Y equals X squared minus 6X + 7 in vertex form

y = (x+3) ^ 2 - 2

ps, the ^ means "to the power of"

Y=x^2-6x+7

vertex form is

y=a (x-h) ^2+k

basically complete the squaer

move 7 over to oth er side

y-7=x^2-6x

look at inner to coplete square

x^2-6x

make sure n umber in front of x^2 is 1, it is

now divide the constant in front of the x term by 2 and square it (-6/3=-3, (-3) ^2=9)

now add that to both sides

y+9-7=x^2-6x+9

comlete the squaer

y+9-7 = (x-3) ^2

add

y+2 = (x-3) ^2

minus 2

y=1 (x-3) ^2-2

equation is

y=1 (x-3) ^2-2