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9 March, 18:23

The length of a rectangle is twice its width. The perimeter is 60 ft. Find its area. In the form of a paragraph, explain in complete sentences the steps necessary to find the area. Include a diagram of the rectangle, the steps used to solve for the area, and the final answer in your explanation.

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  1. 9 March, 20:09
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    Set the following: Length = L Width = W

    The length is twice the width: L = 2*W or: W = L/2

    Perimeter: P = 60ft = 2*L + 2*W

    Substituting L for W in the perimeter equation gives:

    P = 60ft = 2*L + 2 * (L/2) = 2*L + L = 3L

    L = 60ft/3 = 20ft W=L/2=20ft/2=10ft

    Verify result: Perimeter = P = 60ft = 2L + 2W = 2*20ft + 2*10ft = 40ft+20ft = 60ft

    The area of the rectangular is: Area = A = Length*Width = L*W = 20ft*10ft = 200 (ft) ^2

    -Mabel <3
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