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19 December, 14:38

A rectangle pool has an area of 880 square feet. the length is 10 feet longer than the width. Find the dimensions of the pool

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  1. 19 December, 15:47
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    A=LW, and we are told that L=W+10

    Using L=W+10 in A=LW you have:

    A = (W+10) W

    A=W^2+10W

    W^2+10W=880, we are told that A=880 so

    W^2+10W=880 now we can complete the square ...

    W^2+10W+25=905

    (W+5) ^2=905

    W+5=±√905

    W=-5±√905, since W>0

    W=-5+√905 and since L=W+10

    L=5+√905

    W=-5+√905 ft and L=5+√905 ft

    If we want an approximation:

    W≈25.08 ft and L≈35.08 ft (both dimensions to the nearest hundredth)
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