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Mathematics
Cherish Dawson
12 November, 17:59
How to factor 3n^2-17n+24
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Lorenzo
12 November, 20:18
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Find the factors of 3, which are 1, 3 or - 1, - 3, and 24, which can be 1,24; 2,12; 3, 8; 4, 6, negative and positive, and write them this way: factors of 3 to the left, factors of 24 to the right.
then multiply diagonally and add up the products. Keep trying different pairs of factors till you make a - 17
1 - 3
3 - 8
1 * (-8) + 3 (-3) = - 17
so (n-3) (3n-8) is the factored form of the expression
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