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22 March, 23:15

X^3-9x-440=0 (not using factor theorem) and show me how to work it out

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  1. 23 March, 01:09
    0
    We use the method of briot ruffin.

    Where,

    The possible roots are the 440 splitters divided by the coefficient divisors a.

    Divisors of 440 = 440, 220, 110, 88, 55, 44, 40, 22, 20, 11, 10, 8, 5, 4, 2, 1

    Testinh the values, We will see:

    440 / 55 = 8

    This would be one root correct

    Then,

    x^3 - 9x - 440 = 0

    1x^3 + 0x^2 - 9x - 440 = 0

    1, 0, - 9, - 440 | 8

    Downing the number 1, we stay:

    1, 0, - 9, - 440 | 8

    , 8, 64, 440

    1x^2 + 8x + 55 = 0

    Ussing the method of baskara

    a = 1

    b = 8

    c = 55

    Delta = b^2 - 4ac

    Delta = 8^2 - 4. (1). (55)

    Delta = 64 - 220

    Delta = - 156

    To this negative value, Not there is real root.

    Then, just x = 8 It is real.

    Answer:

    X = 8
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