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21 December, 12:57

Y-6=3 (x-1/3)

Need to do equation in slope intercept form

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  1. 21 December, 13:58
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    Given Y-6=3 (x-1/3), we want the slope-intercept form, y = mx + b, where b is the y-intercept.

    Multiplying out 3 (x - 1/3), we get 3x - 1. Then

    Y-6=3 (x-1/3) = > y-6 = 3x - 1

    Adding 6 to both sides, we get:

    y = 3x + 5

    This is in slope-intercept form. The slope is m = 3 and the y-intercept is b = 5.
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