The axis of symmetry for the graph of the function f (X) = 3x^2+bx+4 is X=3/2. What is the value of b?

Remember that the axis of symetry is x=value of how far it is from the origin

also remember that the vertex formula is - b / (2a) so

a=3

3/2=-b / (2 (3))

3/2=-b / (6)

mutiply both sides by 6

18/2=-b

9=-b

multily both sides by - 1

-9=b

so the equation is

f (x) = 3x^2-9x+4

b=-9