If RT is greater than BA, which correctly compares angles C and S? mC = mS mC mS mC ≥ mS

Given two triangles BAC and RTS, with AC congruent to TS and RS conguent to BC.

For any triangle, the longer the side opposite to an angle, the greater the angle.

Thus, given sides RT and BA, with angle S opposite side RT and angle C opposite side BA.

Therefore, given that RT is greater than BA, then angle S must be greater than angle C. (i. e. mC < mS)