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25 December, 19:02
Factor quadratic trinomials 27x^2-90x+27
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Ricardo Robles
25 December, 20:57
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27x^2-81x-9x+27 In this case, just in your mind multiply 27 (coefficient of x^2) by the constant value 27 (the end value of the quadratic trinomial). Then find factors that give you the value - 90 when you add and 729 (27*27) when you multiply.
Factorise the values
27x (x-3) - 9 (x-3)
Which will give you
(27x-9) (x-3)
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