Use substitution to solve each system of equations. If the system does not have exactly one solution, state whether it has no solution or infinitely many solutions.

3x - 2y = 11

x - y/2 = 4

X - y/2 = 4

x - 4 = y/2

2 (x - 4) = y

2x - 8 = y ... so we sub in 2x - 8 in for y in the other equation

3x - 2y = 11

3x - 2 (2x - 8) = 11

3x - 4x + 16 = 11

-x = 11 - 16

-x = - 5

x = 5

2x - 8 = y

2 (5) - 8 = y

10 - 8 = y

2 = y

It has one solution and it is (5,2)