Which equation is equivalent to

log3 (2x4 + 8x3) - 3log3x = 2log3x?

log3 (-x3 + 8x2) = log3x2

-2log3 (2x4 + 8x3 - x) = log3x2

log3 (2x + 8) = log3x2

(the 3 after the log is the base)

This is the concept of algebra, to get the alternative form of the log expression below we simplified it as follows;

log3 (2x^4+8x^3) - 3log3x=2log3x

simplifying the above we get:

log3 (2x^4+8x^3) = 2log3x+3log3x

log3 (2x^4+8x^3) = 5log2x

Hence he answer should be:

log3 (x³) * (log3 (2x+8)) = 5log3 x

3log3 x+log3 (2x+8) = 5log3 x

log3 (2x+8) = 5log3 x-3log3 x

log3 (2x+8) = 2log3 x

log3 (2x+8) = log3 x²

the answer is log3 (2x+8) = log3 x²

The answer is c the thirst one