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16 June, 19:33

Graph y=X^2-3x+4. Find the axis of symmetry and the vertex

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  1. 16 June, 22:58
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    The coordinates of the vertex are (1.5, 1.75) and the axis of symmetry is at x = 1.5.

    We can find the vertex by using the formula for finding x-coordinates. The formula for the x-coordinate of a vertex is below.

    -b/2a

    In this equation, a is the coefficient of the x^2 term (1) and b is the coefficient of the x term (-3). Then we can plug in to find the x term.

    - (-3) / 2 (1)

    3/2

    1.5

    Now that we have this term, we can plug it in for all values of x to find the y term.

    x^2 - 3x + 4

    1.5^2 - 3 (1.5) + 4

    2.25 - 4.5 + 4

    1.75

    Now we know that the vertex is at (1.5, 1.75). Now finding the axis of symmetry is easy because the axis of symmetry in any quadratic is simply x = [x-coordinate of vertex]. So in this case it would be x = 1.5.
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