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16 June, 19:25

The roots of the function f (x) = x2 - 2x - 3 are shown. What is the missing number?

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  1. 16 June, 22:08
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    see below

    Step-by-step explanation:

    f (x) = x^2 - 2x - 3

    To find the roots, set the equation equal to zero

    0 = x^2 - 2x - 3

    Factor, what two numbers multiply to - 3 and add to - 2

    -3 * 1 = - 3

    -3 + 1 = - 2

    0 = (x-3) (x+1)

    Using the zero product property

    x-3 = 0 x+1 = 0

    x=3 x=-1
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