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31 May, 00:37

What's substitution for y=4x-1; y=2x-5

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  1. 31 May, 03:25
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    y = 4x - 1; y = 2x - 5

    Step: Solve y = 4x - 1 for y:

    Step: Substitute 4x - 1 for y in y = 2x - 5:

    y = 2x - 5

    4x - 1 = 2x - 5

    4x - 1 + - 2x = 2x - 5 + - 2x (Add - 2x to both sides)

    2x - 1 = - 5

    2x - 1 + 1 = - 5 + 1 (Add 1 to both sides)

    2x = - 4

    2x / 2 = - 4 / 2 (Divide both sides by 2)

    x = - 2

    Step: Substitute - 2 for x in y = 4x - 1:

    y = 4x - 1

    y = (4) (-2) - 1

    y = - 9 (Simplify both sides of the equation)

    Answer: y = - 9 and x = - 2
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