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Jaxson Koch
11 February, 11:59
I need to know how to factor 16a4-b4
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Parks
11 February, 12:41
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16a⁴ - b⁴
Factorizing powers.
(4a²) ² - (b²) ²
(4a² + b²) (4a² - b²) by difference of two squares.
But (4a² - b²) is also difference of two squares.
(4a² - b²) = (2a) ² - b² = (2a - b) (2a + b)
Therefore:
16a⁴ - b⁴ = (4a² + b²) (4a² - b²) = (4a² + b²) (2a - b) (2a + b)
16a⁴ - b⁴ = (4a² + b²) (2a - b) (2a + b)
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Tucker Wright
11 February, 12:58
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This is a difference of two squares:
(16a^4 - b^4)
= (4a^2 + b^2) (4a^2 - b^2)
This can be further simplified as the second bracket is also a difference of two squares:
(4a^2 + b^2) (4a^2 - b^2)
= 4a^2 + b^2) (2a - b) (2a + b)
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