Determine the discriminant for the quadracic equation 0=-2x^2+3. Based on the discriminant value, how many real number solutions does the equation have?

Discriminant = b^2-4ac

? real number solutions

We are gonna use the formula " Discriminant = b^2-4ac" here to determine the discriminant. We have the value of a=-2; b=0; and c=3. Substituting the values to the formula, we can get the discriminant which is 24. We will then use the rule of discriminant in this problem:

If b² - 4ac > 0, there are two real number solutions

If b² - 4ac = 0, there is one real number solution

If b² - 4ac < 0, there are two imaginary number solutions

Therefore, we can conclude that there will be two real numbers solutions since the discriminant is greater than 0.