The IRS has a group of 45 tax returns, 15 of which contain errors. An IRS auditor randomly selects 3 tax returns from this group. What is the probability the auditor selects none of those containing errors? Round to four decimal places.

Out of 45, there are 45-15=30 that do not contain errors.

If the auditor randomly selects 3 returns, without replacement, then

P (1) = 30/45,

for the second one, there will be 29 correct returns out of 44, so

P (2) = 29/44

Similarly,

P (3) = 28/43

Therefore, by the multiplication rule, the probability of selecting 3 correct returns is the product

P (1) * P (2) * P (3) = 30*29*28 / (45*44*43) = 406/1419