The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field?

The perimeter (P) of a polygon is all the values of all the sides added together. (Length+Length+Width+Width) If the length (L) of the rectangle is 2 feet longer than twice the width (W), then L=2W+2. So now the perimeter is 2W+2+2W+2+W+W = P. This simplifies to 6W+4=P. If we know the perimeter is 244, then 6W+4=244. Then subtract four and divide by 6. W=40. If L=2W+2, then L=2 (40) + 2, or L=82. SO ...

The width is 40 feet

The length is 82 feet

Peri = 2A+2B

244 = 2 (2+2x) + 2 (x)