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13 April, 21:26

If x varies directly as y, and x=18 when y=6 find x when y = 10!

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  1. 14 April, 01:01
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    First thing you need to do is find your k in y = kx

    So to do that insert 18 for x and 6 for y and then solve for k

    y = kx

    6 = k18

    6/18 = k18 / 18

    1 / 3 = k

    k = 1 / 3

    So now that we know what k is we can find x when y = 10. Once again insert the numbers we know. We know k = 1/3 and y = 10 and we need to find x

    y = kx

    10 = (1/3) x

    3 * 10 = 3 * (1/3) x

    30 = x

    x = 30
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