Here are the equations of five straight lines.

Line A. y + 3x = 4

Line B. 2y = x + 1

Line C. y + 2x = 3

Line D. y = 4x - 2

Line E. 2y = 2x - 1

Two of these lines are perpendicular.

Write down the two perpendicular lines.

Step-by-step explanation:

perpendicular lines have negative reciprocal slopes. So we will put each equation in y = mx + b form, and compare the slopes. The slopes, in y = mx + b form, are in the m position.

Line A : y + 3x = 4 ... y = - 3x + 4 ... slope is - 3

Line B: 2y = x + 1 ... y = 1/2x + 1/2 ... slope is 1/2

Line C : y + 2x = 3 ... y = - 2x + 3 ... slope is - 2

Line D: y = 4x - 2 ... slope = 4

Line E: 2y = 2x - 1 ... y = x - 1/2 ... slope is 1

take a look at Line B. it has a slope of 1/2 ... to find the negative reciprocal, all that means is flip the slope and change the sign.

slope 1/2 ... flip it ... 2/1 ... change the sign ... - 2/1 or just - 2.

this means that a line perpendicular to this one will have a slope of - 2 ... and thats the slope Line C has.

so line B and line C are perpendicular <== = because there slopes are negative reciprocals of each other ... slope 1/2 and slope - 2