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2 April, 21:23

In factoring by group how do you solve:

x^3+8x^2-x-8

Also:

y^3-y^2+2y-2

+1
Answers (1)
  1. 2 April, 23:45
    0
    (x + 8) (x + 1) (x - 1)

    (y - 1) (y² + 2)

    Step-by-step explanation:

    x³ + 8x² - x - 8

    Factor from the first two terms:

    x² (x + 8) - x - 8

    And from the last two terms:

    x² (x + 8) - (x + 8)

    Factor:

    (x + 8) (x² - 1)

    Factor the difference of squares:

    (x + 8) (x + 1) (x - 1)

    y³ - y² + 2y - 2

    Factor from the first two terms:

    y² (y - 1) + 2y - 2

    And from the last two terms:

    y² (y - 1) + 2 (y - 1)

    Factor:

    (y - 1) (y² + 2)
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