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20 August, 01:53

Use the X intercept method to find all real solutions of the equation x^3-10x^2+17x+28=0

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  1. 20 August, 03:34
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    They are - 1, 4 and 7.

    Step-by-step explanation:

    x^3 - 10x^2 + 17x + 28 = 0

    Observation of this equation shows that there is an x - intercept at x = - 1 because

    -1^3 - 10^ (-1) ^2 - 17 (1) + 28 = - 28 + 28

    = 0.

    So x + 1 must be a factor so we can do the division:

    x + 1) x^3 - 10x^2 + 17x + 28 (x^2 - 11x + 28

    x^3 + x^2

    -11x^2 + 17x

    -11x^2 - 11x

    28x^2 + 28

    x^2 - 11x + 28 = (x - 4) (x - 7)

    x = 4, 7.
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