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11 January, 03:27

The length of a rectangle is four times its width. If the perimeter is at most 106 centimeters, what is the greatest possible value for the width? Which inequality models this problem?

A. 2w+2 x (46) _< 106

B. 2w + 2 x (4) _> 106

C. 2w+2 x (4w) < 106

D. 2w+2 x (46) > 106

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Answers (2)
  1. 11 January, 04:02
    0
    Answer: A

    Step-by-step explanation: The answer is w≤ 13, which means that the greatest value possible is 13.
  2. 11 January, 04:15
    0
    Greatest possible value for the width is 10.6 centimeters.

    D. 2w+2 * (46) > 106

    Step-by-step explanation:

    Perimeter of a rectangle = 2 (l + w)

    From the given question, P = 106 and l = 4w

    So that,

    106 = 2 (4w + w)

    106 = 2 (5w)

    106 = 10 w

    w = 10.6 centimeters

    So, the greatest possible value for the width is 10.6 centimeters.

    Model; 2w+2 * (46) > 106

    = 2 * 10.6 + 2 * (46)

    = 113.2

    113.2 is greater than 106
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