the sum of three consecutive numbers is one hundred twenty. what is the smallest of the three numbers?

The answer to your question is 39

Step-by-step explanation:

Three consecutive numbers is 120

The smallest is = ?

The smallest will be n

The next one will be = n + 1

The highest will be = n + 2

Now, we add them

n + n + 1 + n + 2 = 120 Simplify like terms

3n + 3 = 120

3n = 120 - 3

3n = 117

n = 117 / 3

n = 39

n + 1 = 40

n + 2 = 41

39 + 40 + 41 = 120