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29 August, 07:48

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains

80

%

pure antifreeze. The company wants to obtain

320

gallons of a mixture that contains

55

%

pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed?

+5
Answers (1)
  1. 29 August, 08:15
    0
    let w = amt of water required

    :

    An equation based on the the percent water, an 80% solution is 20% water.

    .20 (320-w) + w =.50 (320)

    64 -.2w + w = 160

    .8w = 160 - 64

    w = 96%2F. 8

    w = 120 gal of water to produce 320 gal of 50% antifreeze

    :

    320 - 120 = 200 gal of 80% solution

    Water: _120___ gallons

    Premium Antifreeze: __200___ gallons
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