What is the domain of the function

f (x) = square root of (1/3) x+2?

The domain of f (x) = √[ (1/3) x + 2] is [-6, ∞).

Step-by-step explanation:

GIven f (x) = √[ (1/3) x + 2], you have to find the values for which the the expression inseide the square will be possitive (for negative values the function is not defined for Reals.

(1/3) x + 2 = 0 ⇒ (1/3) x = - 2 ⇒ x = - 2 / (1/3) ⇒ x = - 6

Finally the domain of f (x) is (-6, ∞).