Find the zeros of f (x) = x^2 + 2x - 8.

A. {1, 8}

B. {-2,4}

{2,-4}

D. {-1, - 8)

f (x) = x^2 + 2x - 8

Factor the polynomial by finding 2 numbers that when added together would equal 2 and when multiplied together would equal - 8.

The factored form is (x-2) (x+4)

Now find the zero's by solving for the two x's:

x = 2 and x = - 4

The answer would be {2,-4}