Human body temperatures are normally distributed with a mean of 98.20oF and a standard deviation of 0.62oF If 19 people are randomly selected, find the probability that their mean body temperature will be less than 98.50oF. Your answer should be a decimal rounded to the fourth decimal place

Step-by-step explanation:

Since the human body temperatures are normally distributed, the formula for normal distribution is expressed as

z = (x - u) / s

Where

x = human body temperatures

u = mean body temperature

s = standard deviation

From the information given,

u = 98.20oF

s = 0.62oF

We want to find the probability that their mean body temperature will be less than 98.50oF. It is expressed as

P (x lesser than 98.50)

For x = 98.50,

z = (98.50 - 98.20) / 0.62 = 0.48

Looking at the normal distribution table, the corresponding probability to the z score is 0.6844

P (x lesser than 98.50) = 0.6844