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22 October, 01:08

How do I write an equation of a line that passes through (0,3) and (-5, 2.5)

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  1. 22 October, 03:13
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    y=1/10x+3

    Step-by-step explanation:

    m = (y2-y1) / (x2-x1)

    m = (2.5-3) / (-5-0)

    m=-0.5/-5

    m=0.5/5

    m = (1/2) / 5

    m = (1/2) (1/5)

    m=1/10

    y-y1=m (x-x1)

    y-3=1/10 (x-0)

    y-3=1/10 (x)

    y-3=1/10x

    y=1/10x+3
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