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12 March, 06:53

10-kg batch of a food product has a moisture content of175% dry basis. Calculate the amount of water to beremoved from the product to reduce the moisture content to15% wet basi

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  1. 12 March, 08:40
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    4.9kg of water

    Step-by-step explanation:

    Dry basis is the percentage ratio of moisture amount to amount of dry product which is 175%

    Ratio of moisture amount to dry product = 175 : 100

    Mass of food product = 10kg

    Amount of moisture in food product = 175/175+100 * 10kg = 175/275 * 10kg = 6.4kg

    Wet basis is the percentage ratio of the moisture amount to the total weight of material which is 15%

    Ratio of moisture amount to total weight of material is 15 : 100

    Amount of moisture in food product = 15/100 * 10kg = 1.5kg

    Amount of water contained in the final product = 1.5kg

    Amount of other components in the food product = 10kg - 6.4kg = 3.6kg

    Total amount = 1.5kg + 3.6kg = 5.1kg

    % of water = 1.5kg/5.1kg * 100 = 29%
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