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3 November, 18:27

What substitution should be used to rewrite 16 (x + 1) 2 - 22 (x + 1) - 3 = 0 as a quadratic equation?

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  1. 3 November, 20:58
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    see explanation

    Step-by-step explanation:

    Given

    16 (x + 1) ² - 22 (x + 1) - 3 = 0

    Using the substitution u = x + 1, then

    16u² - 22u - 3 = 0 ← quadratic equation in standard form
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