A phone company offers two packages of service. Package A is $35.00 per month with an additional charge of $0.15 per minute for long distance. Package B is $45.00 per month with an additional charge of $0.10 per minute for long distance. How many minutes have to be used for the costs of both plans to be the same?

Question

Mathematics

Guest

30 September, 12:34

A phone company offers two packages of service. Package A is $35.00 per month with an additional charge of $0.15 per minute for long distance. Package B is $45.00 per month with an additional charge of $0.10 per minute for long distance. How many minutes have to be used for the costs of both plans to be the same?

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Addie · Answer 1

Answer: 200 minutes have to be used for the costs of both plans to be the same.

Step-by-step explanation:

Let x represent the number of minutes that have to be used for the costs of both plans to be the same.

Package A is $35.00 per month with an additional charge of $0.15 per minute for long distance. This means that the cost of using package A for x minutes in a month would be

35 + 0.15x

Package B is $45.00 per month with an additional charge of $0.10 per minute for long distance. This means that the cost of using package A for x minutes in a month would be

45 + 0.1x

For both costs to be the same, it means that

35 + 0.15x = 45 + 0.1x

0.15x - 0.1x = 45 - 35

0.05x = 10

x = 10/0.05

x = 200