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20 November, 09:01

The integers m and p are such that 2 < m 1? (1) The greatest common factor of m and p is 2. (2) The least common multiple of m and p is 30.

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  1. 20 November, 10:26
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    Yes. r>1

    Step-by-step explanation:

    First we write the information we have.

    2
    (1) The greatest common factor is 2. So we can say

    2 is a factor of m and p.

    (3) The minimum common multiple of m and p is 30.

    So we can say that 30 can be divided by m and also by p.

    So we will write all the dividers of 30.

    1; 2; 3; 5; 6; 10; 15; 30

    Of all this integers, the only ones that can be divided by 2 are:

    2. 6 and 10.

    Also, we know that m is not a factor of p. So we know that it cant be 2. because both 6 and 10 can be divided by 2.

    That means m = 6 and p = 10.

    So if r is the remainder of p divided by m. When we divided 10 by 6, we have a remainder of 4. r=4. Then r>1.
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