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8 July, 03:01

What are the solutions to 2x^2+7y=4? Select all that apply.

1/2

4

-1/2

-4

7

-7

+3
Answers (1)
  1. 8 July, 06:47
    0
    x = - 1/2, 4

    Step-by-step explanation:

    1) If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

    2x+1=0

    x-4=0

    2) Set the first factor equal to 0.

    2x+1=0

    3) Subtract 1 from both sides of the equation.

    2x=-1

    4) Divide each term by 2 and simplify.

    2x/2 = - 1/2

    5) Cancel the common factor of 2.

    x = - 1/2

    6) Move the negative in front of the fraction.

    x = - 1/2

    7) Set the next factor equal to 0 and solve.

    x=4

    8) The final solution is all the values that make

    (2x+1) (x-4) = 0 true.

    9) x = - 1/2, 4
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