W (x) = 3•3^x+3 + 2; solve for w (-2)

11

Step-by-step explanation:

We evaluate W (x) = 3•3^x+3 + 2 at x = - 2 by substituting - 2 for each instance of x:

But first note that we must enclose x + 3 inside parentheses:

W (x) = 3•3^ (x+3) + 2.

Substituting - 2 for x, we get:

W (-2) = 3•3^ (-2+3) + 2, or

W (-2) = 3•3^ (1) + 2, or

W (-2) = 9 + 2 = 11