How would you solve dy/dx = 4x - 2, y (-1) = 1 using differential equations?

y=2 (x square) - 2x-3

Step-by-step explanation:

Let dy with y varibles in a hand

And dx with x variables on the other hand

dy = (4x-2) dx

Then by integration

y=2 (square x) - 2x+constant

Then substitute by x=-1 and y=1 to find the value of the constant

1=2 (1) - 2 (-1) + constant

Then constant=-3

Then the equation is

y=2 (x square) - 2x-3