In changing a tire a hydraulic jack lift 7468 newtons on its large piston which has an area of 28.27 cm squared how much force must be exerted on the small piston if it has an area of 1.325 cm squared

Answer: 349.99 Newton must be exerted on the small piston

Step-by-step explanation:

In changing a tire a hydraulic jack lift 7468 newtons on its large piston which has an area of 28.27 cm squared. Pressure is expressed as force/area

Pressure exerted and transmitted to the smaller piston is

7468/28.27 = 264.14N/cm²

If the small piston has an area of 1.325 cm squared, the force that would be exerted on the smaller piston is

Force = pressure * area

= 264.14 * 1.325 = 349.99 Newton