4x-8y=6. 2x-4y=3

linear system algebraically

Solve for x first

4x - 8y + 8y = 6 + 8y - Add 8y to both sides

4x = 8y + 6

4x 4 = 8y + 6 4 - Divide both sides by 4

x = 2y + 3 2

then use subsitution

2x - 4y = 3

2 (2y + 32) - 4y = 3

3=3 - Simplify both sides of the equation

3 + - 3 = 3 + - 3 - Add - 3 to both sides

0=0