How do you get 2b+8 factored?

Version one: equation is equal to 0

Given equation

2

b

+

8

that equals zero,

2

b

+

8

=

0

Isolate the 2b by subtracting 8 from each side

2

b

+

8

-

8

=

0

-

8

→

2

b

=

-

8

Divide both sides by 2 to isolate b

2

b

2

=

-

8

2

→

b

=

-

8

:

2

=

-

4

Version two: no quantity equivalence

GIven function

2

b

+

8

we can apply the Distributive Property

convert to proper form

2

b

+

8

⇒

2

(

b

)

+

2

(

z

)

where

2

z

=

8

To get variable

z

⇒

8

:

2

=

z

=

4

, therefore you have

2

(

b

)

+

2

(

4

)

or in factored form,

2

(

b

+

4

)

2 (b + 4)

Step-by-step explanation:

First you rewrite 8 to be 4 times 2

2b + 2 * 4

Then you simply factor out the common term of 2