Find the distance between xequals[Start 2 By 1 Matrix 1st Row 1st Column 8 2nd Row 1st Column negative 5 EndMatrix ]and yequals[Start 2 By 1 Matrix 1st Row 1st Column negative 1 2nd Row 1st Column negative 9 EndMatrix ].

Distance = √ (x₁ - y₁) ² + (x₂ - y₂) ² = √97 = 9.85

Step-by-step explanation:

The Matrix X and Y could also be referred to as vectors in Rⁿ dimensions.

if Vector X = (x₁, x₂) and Vector Y = (y₁, y₂)

then, Distance (X-Y) = ||X-Y|| = √ (x₁ - y₁) ² + (x₂ - y₂) ²

where, x₁ = 8, x₂ = - 5 and y₁ = - 1, y₂ = - 9

Distance = √ (8 - (-1)) ² + (-5 - (-9)) ² = √9² + 4² = √97 = 9.85