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29 November, 13:17

Find the length and width of the rectangle described. The length is 12 units more than the width. The perimeter is 7 times the width.

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  1. 29 November, 14:10
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    The length is 20 units. The width is 8 units.

    Step-by-step explanation:

    The width is an unknown, so we will let W = the width.

    The length is also an unknown, but we know the length is 12 units more than the width, so the length is L = W + 12.

    The perimeter is 7 times the width. P = 7W

    The perimeter is also the sum of two lengths and two widths.

    P = 2L + 2W

    7W = 2 (W + 12) + 2W

    7W = 2W + 24 + 2w

    7W = 4W + 24

    3W = 24

    W = 8

    The width is 8 units.

    L = W + 12

    L = 8 + 12 = 20

    The length is 20 units.
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