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Mathematics
Mueller
16 March, 13:19
The binomial expansion of (x-2y) ^3 is?
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Ari
16 March, 13:41
0
x^3 - 6x^2y - 12xy^2 - 8y^3
Step-by-step explanation:
(x-2y) ^3
There are three parts to binomial expansion - the coefficient, the power of the first term and the power of the second term.
Use Pascal's Triangle to find the coefficient.
^3 = 1 3 3 1
The first term's powers are descending:
x^3 x^2 x^1 x^0
The second term's powers are ascending.
-2y^0 - 2y^1 - 2y^2 - 2y^3
The first coefficient is multiplied by the first power of the first term and the first power of the second term.
3C0 x^3 (-2y) ^0 = 1 x^3 1 = x^3
2C1 x^2 (-2y) ^1 = 3 x^2 - 2y = - 6x^2y
1C2 x^1 (-2y) ^2 = 3 x - 2y^2 = - 12xy^2
0C3 x^0 (-2y) ^3 = 1 1 - 2y^3 = - 8y^3
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Jeramiah Kramer
16 March, 15:12
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x^3 - 6x^2y + 12xy^2 - 8y^3
Step-by-step explanation:
(x-2y) ^3
= (x - 2y) (x - 2y) ^2
= (x - 2y) (x^2 - 4xy + 4y^2)
= x^3 - 4x^2y + 4xy^2 - 2x^2y + 8xy^2 - 8y^3
= x^3 - 6x^2y + 12xy^2 - 8y^3
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