F (x) = 3x2 + 12x + 5

What is the value of the discriminant of f?

How many distinct real number zeros does f (2) have?

Discriminate is 84

And F (2) is 41

Step-by-step explanation:

Discriminate of a quadratic equation is given by

D=b^2-4aC

Given

F (x) = 3x^2+12x+5

a=3, b=12 and C=5

D = 12^2-4*3*5=84

For F (2)

F (2) = 3 (2) ^2+12 (2) + 5=41