the length of a rectangle is 7 inches more than its width, if the perimiter of the rectangle is 66 inches, find its dimensions.

Perimeter of rectangle=66

length of rectangle=L

width of rectangle=w

P of a rect. = 2 (length) + 2 (width)

66 = 2L+2w

if the length is 7in more than the width, then

L=7+w

Now we will substitute 7+w in for L. Here is our new equation:

66=2 (7+w) + 2w

Solve for w

66=14+2w+2w

66=14+4w

52=4w

w=13

L=7+13, so L=20

I hooe this is explained well enough