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Mina Hatfield
31 March, 06:57
How do i tell if y=x^3+x^2 is even or odd?
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Kyle Bond
31 March, 10:27
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If a function is even, then f (-x) = x.
If a function is odd, then f (-x) = - x.
y = x³ + x² → f (x) = x³ + x² → - f (x) = - (x³ + x²) = - x³ - x²
f (-x) = (-x) ³ + (-x) ² = [ (-1) (x) ]³ + [ (-1) (x) ]² = (-1) ³x³ + (-1) ²x²
= - 1x³ + 1x² = -x³ + x²
f (-x) ≠ f (x) and f (-x) ≠ - f (x)
y = x³ + x² is not odd and not even
Answer: neither
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