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23 May, 16:36

how much wrapping paper would you need to cover a rectangular that is 18.25 inches by 12inches by 3 inches if you need 10% more wrapping paper than the surface area of the box? give your answer to the nearest square inch

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  1. 23 May, 19:14
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    Answer: 681 square inch

    Step-by-step explanation:

    Hi, we have to apply the formula for the surface area:

    A = 2wl + 2lh + 2hw

    Where:

    w: width

    l: length

    h: height

    Replacing with the values given:

    A = (2x12x18.25) + (2x12x3) + (2x18.25x3)

    A = 438+72+109.25

    A=619.5 in2

    Since it has to be 10% more than the surface.

    619.5 x (10/100) = 61.95 in2

    Adding that value to the surface area

    619.5+61.95 = 681.45in2 = 681 in2
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