A 12 sided die with sides labeled 1 through 12 will be rolled once each number greater than 10?

Answer: I think you're missing something on your question. But I think what your asking is how many numbers greater than 10. It should 2/12 or

See the explaination

Step-by-step explanation:

Total No. of rolling each side of the 12-sided die = 12 x 12 = 144 outcomes

No. of outcomes equals 10 are: (1, 9), (9, 1), (2, 8), (8, 2), (3, 7), (7, 3), (4, 6), (6, 4), (5, 5) = 9 outcomes.

No. of outcomes of rolling a No. >10: 144-9 = 135 outcomes.

Probability, Pr, of rolling a No. >10 = 135/144

Pr (No. >10) = 0.9375 (to 4 dec. pl.)