Ask Question
27 January, 06:57

Which system of equations has a solution of approximately (1.8,-0.9)

A. 6x-5y=15 and x+2y = 0

B. 4x+5y=8 and 6x-5y=15

C. x-2y=4 and 4x+5y=8

D. 6x-5y=15 and x-2y=4

+5
Answers (2)
  1. 27 January, 07:11
    0
    Solve the equation systems or set the values x = 1.8 and y = - 0.9 on the equation and check the equality.

    A.

    6x - 5y = 15

    L = 6 (1.8) - 5 (-0.9) = 10.8 + 4.5 = 15.3

    R = 15

    L ≈ R

    x + 2y = 0

    L = 1.8 + 2 (-0.9) = 1.8 - 1.8 = 0

    L = R

    B.

    4x + 5y = 8

    L = 4 (1.8) + 5 (-0.9) = 7.2 - 4.5 = 2.7

    R = 8

    L ≠ R

    C.

    x - 2y = 4

    L = 1.8 - 2 (-0.9) = 1.8 + 1.8 = 3.6

    R = 4

    L ≈ R

    4x + 5y = 8

    L = 4 (1.8) + 5 (-0.9) = 7.2 - 4.5 = 2.7

    R = 8

    L ≠ R

    D.

    6x - 5y = 15

    L = 6 (1.8) - 5 (-0.9) = 10.8 + 4.5 = 15.3

    R = 15

    L ≈ R

    x - 2y = 4

    L = 1.8 - 2 (-0.9) = 1.8 + 1.8 = 3.6

    R = 4

    L ≈ R

    We have two probability solutions: A and D.

    But I think, Your answer is A.
  2. 27 January, 08:23
    0
    A.

    6x - 5y = 15

    L = 6 (1.8) - 5 (-0.9) = 10.8 + 4.5 = 15.3

    R = 15

    L ≈ R

    x + 2y = 0

    L = 1.8 + 2 (-0.9) = 1.8 - 1.8 = 0

    L = R

    B.

    4x + 5y = 8

    L = 4 (1.8) + 5 (-0.9) = 7.2 - 4.5 = 2.7

    R = 8

    L ≠ R

    C.

    x - 2y = 4

    L = 1.8 - 2 (-0.9) = 1.8 + 1.8 = 3.6

    R = 4

    L ≈ R

    4x + 5y = 8

    L = 4 (1.8) + 5 (-0.9) = 7.2 - 4.5 = 2.7

    R = 8

    L ≠ R

    D.

    6x - 5y = 15

    L = 6 (1.8) - 5 (-0.9) = 10.8 + 4.5 = 15.3

    R = 15

    L ≈ R

    x - 2y = 4

    L = 1.8 - 2 (-0.9) = 1.8 + 1.8 = 3.6

    R = 4

    L ≈ R

    Yeah so your answer is gonna be

    A.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Which system of equations has a solution of approximately (1.8,-0.9) A. 6x-5y=15 and x+2y = 0 B. 4x+5y=8 and 6x-5y=15 C. x-2y=4 and 4x+5y=8 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers