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15 December, 21:24

What is the vertex of this parabola y=-4x^2+8x-12

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  1. 15 December, 23:34
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    The answer you are looking for is (1, - 8)

    remember that: x=[ (-b/2a) ]

    and that the problem is set up as y=ax^2+bx+c

    calculate:

    x=[-8/2 (-4) ]

    x=[-8/-8]

    x=1

    then:

    y = (-4) * 1^2 + (8*1) - 12

    y = (-4) + 8-12

    y = (-4) + 8-12

    y=4-12

    y = (-8)

    (1, - 8)
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